Wawrinka gặp Djokovic ở bán kết Úc mở rộng 2015
TTO - Đương kim vô địch Giải Úc mở rộng Stan Wawrinka (Thụy Sỹ, hạt giống số 4) đoạt vé vào chơi trận bán kết sau khi hạ hạt giống số 5 người Nhật Bản Kei Nishikori 3-0 (6-3, 6-4, 7-6) ở tứ kết. Bước ngoặt mang đến chiến thắng cho Wawrinka ở hai ván đấu đầu tiên chính là hai lần bẻ break ở bàn đấu Nishikori cầm giao bóng. Sau đó, tay vợt người Thụy Sỹ tận dụng tuyệt đối ưu thế cầm giao bóng để giành thắng lợi chung cuộc.
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